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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by JD Vila
JD Vila
8,095 Points

This works in my IDE, but not in Workspaces...

Why won't this compile for wordcount.py?

def word_count(sentence): new_sentence = sentence.lower().split(" ") new_dict = {} for word in new_sentence: new_dict[word] = new_sentence.count(word) return new_dict

Please and thank you!!!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(sentence):
    new_sentence = sentence.lower().split(" ")
    new_dict = {}
    for word in new_sentence:
        new_dict[word] = new_sentence.count(word)
    return new_dict

1 Answer

Christian Mangeng
Christian Mangeng
15,970 Points
Christian Mangeng
Christian Mangeng
15,970 Points

Hi Jose,

it works if you do not explicitly define a space in the split command. Just use .split() instead of .split(" ").

JD Vila
JD Vila
8,095 Points

Oh man, thank you so much!!!