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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Ian Darby
Ian Darby
1,455 Points

Thoroughly stumped on this one.

It seems so perfect to me? Why would it not print anything?

Thanks, Ian

even.py 
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while not start:
    num = random.randint(1, 99)
    if even_odd(num):
        print('{} is even'.format(num))
    else:
        print('{} is odd'.format(num))
    start = start - 1

1 Answer

Ari Misha
Ari Misha
19,323 Points
Ari Misha
Ari Misha
19,323 Points

Hiya there! You're very close but you got confused with the challenge a bit i guess. The challenge says the "while" loops needs to run until "start" is "falsey" right? In other words, "while" loops needs to run until it encounters something falsey in your code aka something to break out. Hence your code needs to look like this:

import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start:
    num = random.randint(1, 99)
    if even_odd(num):
        print('{} is even'.format(num))
    else:
        print('{} is odd'.format(num))
    start -= 1

Also, dont forget the PEP 8 rule for Python, so yeah always implement that in your code. I hope it helped! (: