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Start your free trialTomme Lang
1,118 PointsTrouble with teachers.py task 4 of 5
I really want to use count/max for this, but cant figure out where to put it. I think I am making this much harder than it has to be. I've included task 1 through 3 incase there is something in there that has tripped me up.
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict):
return len(dict)
def num_courses(dict):
list = []
for v in dict.values():
list += v
return len(list)
def courses(dict):
new_list = []
for v in dict.values():
for v in v:
new_list.append(v)
return new_list
def most_courses(dict):
most_list = []
for k in dict():
for max_courses in dict[k]:
most_list.append(max_courses)
return (most_list)
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsThe missing piece is how to
- track the maximum number of courses seen so far
- compare this maximum to the current teachers course count
- if a new maximum is found,
- save the name of the teacher
- save the new maximum
You can get the number of courses for the current teacher using len(max_courses)
.
Remember to initialize the current maximum course count at 0 before the loop to compare courses.
Be sure to return the name of the teacher with the maximum course count.
Post back if you need more help. Good luck!!
Tomme Lang
1,118 PointsTomme Lang
1,118 PointsGot it, finally. Thanks. That one had me stumped