try and except 1/3

I understand that you are having a problem with this challenge, as you have not specified which part exactly you are stuck on, I will explain each part of the challenge step by step.

Task 1:

def add(a, b):
    return a + b

This first task is simple, this function takes in 2 arguments which are integers. It adds them both together then returns the sum of them both.

Task 2:

In the second task, you have to convert the 2 arguments into floats before you add them. You can do this using the float() function. You can shorten this code by assigning both variables in one line. Either of the 2 solutions below will work:

def add(a, b):
    a = float(a)
    b = float(b)
    return a + b

def add(a, b):
    a, b = float(a), float(b)
    return a + b

Task 3:

Finally, in task 3, we need to handle a situation where instead of 2 integers, something like a string is passed in. We need to try to convert both arguments to floats. However, if there is a ValueError, we should return the value None. You can do this with the following code, I will add comments to explain what each part does:

def add(a, b):          #define function named add which takes 2 arguments
    try:                #try to do the following:
        a = float(a)
        b = float(b)
    except ValueError:  #If there is a ValueError
        return None     #return None because this means either one or both of the arguments are not an integer
    return a + b        #Finally, if there is no value error, add the two floats together and return the total

I hope i solved your problem and that you understand now!