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Python Python Basics (2015) Number Game App Number Game Refinement

Curtis Crawley
Curtis Crawley
550 Points

Trying to Break code!! When i put in a non-integer in for guess it always comes back as invalid literal for int().

Am I missing something? Heres my code. Please help.

import random

def game():

secret_num = random.randint(1, 10)
guesses = []

while len(guesses) < 5:
    try:
        guess = int(input("Guess a number between 1 and 10: " ))
    except ValueError:
        print("{} isn't a number!".format(guess))
        break
    else:
        if guess == secret_num:
            print("You got it! My number was {}".format(secret_num))
            break
        elif guess < secret_num:
            print("My number is higher than {}".format(guess))
        else:
            print("My number is lower than {}".format(guess))
        guesses.append(guess)
else:
    print("You didn't get it! My number was {}".format(secret_num))
play_again = input("Do you want to play again? Y/N ")
if play_again.lower() != "N":
    game()
else:
    print("Bye")

game()

2 Answers

Steven Parker
Steven Parker
230,995 Points

:point_right: I also got that error, but only because it was accompanied by this one:

      During handling of the above exception, another exception occurred:
      UnboundLocalError: local variable 'guess' referenced before assignment

Your handler tried to reference guess, but the exception occurred before it was assigned. You may want to change your message to something simpler like this:

        print("That isn't a number!")

Otherwise, you'd need to store the string from the prompt in a separate variable, and then convert it to int on another line.

Also, I noticed this line which can never be false, because anything lowered can never be upper case:

    if play_again.lower() != "N":

You can either change lower to upper or change "N" to "n".