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Python Python Basics (2015) Number Game App Squared

Posted by Matt Duarte
Matt Duarte
2,497 Points

Trying to turn an argument into an int

Hey I am trying to turn the argument into an int, but it keeps saying syntax errordef squarerd("5"). Is my code right?

def squared("5"): try: arg2 = "This"
if arg == int("5"): return arg**2 else: return arg2*len()

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared("5"):
    try:
        arg = "This"        
    if arg == int("5"):
        return arg**2
    else:
        return arg*len()

1 Answer

Steven Parker
Steven Parker
230,995 Points
Steven Parker
Steven Parker
230,995 Points

Here's a few hints:

  • a function parameter name can't be a number or have quotes around it
  • a "try" must have a matching "except"
  • you won't need to create any new string values in this challenge
  • the code inside a try must do something that might cause an exception (not just an assignment)
  • the len function must have an argument