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14,091 PointsTypeError: int() argument must be a string, a bytes-like object or a number, not 'D6'
MY CODE:
import random
class Die: def init(self, sides=2, value=0): if not sides >=2: raise ValueError("Must have at least 2 sides or more") if not isinstance(sides, int): raise ValueError("Sides must be a whole number") self.value = value or random.randint(1,sides)
def __int__(self):
return self.value
def __eq__(self, other):
return int(self) == other
def __ne__(self, other):
return int(self) != other
def __gt__(self,other):
return int(self)>other
def __lt__(self,other):
return int(self)<other
def __ge__(self, other):
return int(self) > other or int(self) == other
def __le__(self, other):
return int(self) < other or int(self) == other
class D6(Die): def init(self, value =0): super().init(sides=6, value=value)
MY ERROR:
d1 = D6()
d2 = D6()
int(d1)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: int() argument must be a string, a bytes-like object or a number, not 'D6'
I saw someone else had the same issue but forgot to include the "def int(self): return self.value". I have that in there and it is still giving me the same error msg.
2 Answers
dararoberts5
2,134 PointsI also had this error and it was because my indentation block was too far in, make sure it's in line with the other methods within the class.
Steven Parker
231,198 PointsThis code seems to be OK, but it's hard to be sure with unformatted Python. Please use Markdown formatting so the code is shown as it is actually written.