Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialAiza Farhaj
9,670 Points<ul> <?php foreach($flavors as $flavor) { ?> <li><?php echo $flavor; ?></li> <?php } ?> </ul>
y this code is not working
<?php
$flavors = array("Chocolate","Vanilla","aaa");?>
<ul>
<?php foreach($flavors as $flavor) { ?>
<li><?php echo $flavor; ?></li>
<?php } ?>
</ul>
<p>Welcome to Ye Olde Ice Cream Shoppe. We sell <?php echo count($flavors); ?> flavors of ice cream.</p>
<ul>
<li><?php echo $flavor1; ?></li>
<li><?php echo $flavor2; ?></li>
</ul>
1 Answer
Damien Watson
27,419 PointsHi Aiza,
Your new unordered list should replace the old one, so just copy your new list over the top, like this:
<?php $flavors = array("Chocolate","Vanilla","aaa"); ?>
<p>Welcome to Ye Olde Ice Cream Shoppe. We sell <?php echo count($flavors); ?> flavors of ice cream.</p>
<ul>
<?php foreach($flavors as $flavor) { ?>
<li><?php echo $flavor; ?></li>
<?php } ?>
</ul>
Aiza Farhaj
9,670 PointsAiza Farhaj
9,670 PointsThanks Damien get the point