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Start your free trialDaniel Williams
Courses Plus Student 1,325 PointsUnable to console log this from 4 to 156.
tried reviewing the concepts in the associated video somehow still lost in this.
var number= '';
for (var i =4; i <=156; i += 1) {
i += 'number' + i + 'number';
}
console.log(number + i);
2 Answers
Emre Karakuz
9,162 PointsFirst of all, you don't need a varible name = ' ' to do this challenge
2-)You are already increasing the i value in the loop decleration with this code : ( i=4 ; i<=156; i += 1). So you dont need to increase it in the function block (between {})
3-) console.log is called after the for loop which means it will log the last i variable (156) to the console. To fix this, write console.log(i) inside the for loop.
for (var i =4; i <=156; i += 1) {
console.log(i);
}
katherine
45,330 PointsWhen using a variable, such as number in this case, you aren't supposed to put quotes around it when referencing it. The quotes make JavaScript interpret it as a string. For this exercise, however, you don't need the number variable. Just the i variable should suffice. Also, your console.log() statement should be inside the for loop, not underneath it. Try this instead:
for (var i =4; i <=156; i += 1) {
console.log(i);
}
Daniel Williams
Courses Plus Student 1,325 PointsI loved your explanation as well. I am truly grateful for this. I guess I still have a lot of practice and learning to go.
Nick Ruiz
18,492 PointsBasically what katherine said, this was how I wrote it.
for (var i = 4; i <= 156; i++){
console.log(i);
}
the "i++" increment is shorthand for "i += 1" that you may see in some other languages.