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Python Python Basics (2015) Logic in Python Conditional Value

Subramanian K
Subramanian K
3,103 Points
Posted by Subramanian K
Subramanian K
3,103 Points

Unorderable type Error. NoneType()<int()

I'm going to create a variable named age. I need you to make an if condition that sets admitted to True if age is 13 or more.

conditions.py 
admitted = None
age = 13
if age>admitted:
    print("true")

5 Answers

Ted Dunn
Ted Dunn
43,783 Points

The challenge states that a variable called age will be created for you so you do not need to create and initialize the variable age = 13.

The challenge is asking you check if age is greater than 13; if this is true, change admitted to True.

if age > 13:
    admitted = True
Iain Simmons
MOD
Iain Simmons
Treehouse Moderator 32,305 Points
Iain Simmons
Iain Simmons
Treehouse Moderator 32,305 Points

You're trying to compare an integer to None, which you can't do.

You don't need to set the age, it says that that will be done for you.

You just need to check if the age is greater than or equal to 13.

Then set admitted to True if that condition matches.

Subramanian K
Subramanian K
3,103 Points
Subramanian K
Subramanian K
3,103 Points

Thanks @Ted Dunn and @Iain Simmons It works.

Nate Paul
Nate Paul
11,885 Points
Nate Paul
Nate Paul
11,885 Points

admitted = None age = 13

if age >= 13: admitted = True

Gonzalo Torres del Fierro
PLUS
Gonzalo Torres del Fierro
Courses Plus Student 16,751 Points
Gonzalo Torres del Fierro
Gonzalo Torres del Fierro
Courses Plus Student 16,751 Points

be aware of indentation too, it is possible that the code does not work just for that (use tab key)