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Python Python Basics (2015) Letter Game App Even or Odd Loop

Dennis Moriarity
PLUS
Dennis Moriarity
Courses Plus Student 940 Points
Posted by Dennis Moriarity
Dennis Moriarity
Courses Plus Student 940 Points

Unsure of what i need to code

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1.

even.py 
import random

start = 5
def even_odd(num):

while True:
    randon_number = random.randint(1, 99)
    if num % 2 == 0: 
        print("{} is even").format(num)
    else:
        print("{} is odd").format(num)

else:
    break
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

2 Answers

Christopher Shaw
seal-mask
PLUS
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points
Christopher Shaw
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points

You have a few errors:

  1. you have messed up the function even_odd, provided for you.

  2. .format needs to be inside the print brackets and change num to random_number

  3. No need for the else

  4. decrement start each time the while loop runs

  5. while start is the same as while start == True, become false when start == 0

import random 

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    randon_number = random.randint(1, 99)
    if even_odd(randon_number):
        print("{} is even".format(randon_number))
    else:
        print("{} is odd".format(randon_number))
    start = start - 1