Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Warren Chisasa
3,731 PointsUse of 'pop' and 'insert' function
I am trying to remove the first element of my list then add 1 to it by using the pop and insert function in one step but I keep getting the 'bummer'. Requesting for any suggestions on how to deal with this code.
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
new_list = the_list.pop(0).insert(0,1)
print(new_list)
# Your code goes below here
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsIn your code, the pop(0) removes the first object from the list and returns it. This is the string "a". It is this object that is referenced by the insert() method. Strings do not have this method so it raises an error.
new_list = the_list.pop(0).insert(0,1)
Instead, use each method separately so they can operate directly on the list.
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
the_list.pop(0) # remove string
the_list.insert(0, the_list.pop(2)) # remove 1, insert at first position