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Python Python Collections (Retired) Lists Redux Manipulating Lists

Mateo Rial
Mateo Rial
3,694 Points
Posted by Mateo Rial
Mateo Rial
3,694 Points

Use .remove() and/or del to remove the string, boolean, and list members of the_list. wtf is wrong????

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

the_list.insert(0,the_list.pop(2)) the_list.remove("a") the_list.remove(False) del the_list[-1] print(the_list)

lists.py 
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

the_list.insert(0,the_list.pop(2))
the_list.remove("a")
the_list.remove(False)
del the_list[-1]

# Your code goes below here

3 Answers

Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi Mateo,

I'm not sure how you passed task 1 but the one is at index 3. You should pop the item at index 3.

Your remove and del statements are fine for task 2.

Vinod Purushothaman
Vinod Purushothaman
2,970 Points
Vinod Purushothaman
Vinod Purushothaman
2,970 Points

Please tell me why this doesn't work.

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
the_list.insert(0, the_list.pop(3))
for item in the_list:
    if type(item) != int:
        the_list.remove(item)
    else:
        continue
Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi Vinod,

Modifying a list while you're looping over it can have unintended consequences. Particularly, removing items.

When False is removed, the list after it moves down 1 index to occupy that spot. When it loops again, it's trying to look at the next index but there's nothing there so the loop ends.

It effectively skips over the list [1, 2, 3]

Instead, you could loop over a copy of the list while you remove items from the original list. This insures that every item gets looked at.

for item in the_list[:]: # using slice notation to get a copy of the_list