Using forEach, iterate over the colors array and store the hex colors that start with the letter F (ex. #FF0000) in the

Question

How come this doesn't work and why is the solution method different from the initial challenge?
```app.js
const colors = ['#87E2D0', '#559F4D', '#FFE0F4', '#7E7E7E', '#FF2D2D', '#F7FFEC'];
let filteredColors = [];
// filteredColors should be: ['#FFE0F4', '#FF2D2D', '#F7FFEC']
// Write your code below
colors.forEach(color => {
  if(color === 'F' ) {
    filteredColors.push(color);
  }
});
```

Henry Blandon · Answer

Hello @Dionte Barnes (https://teamtreehouse.com/diontebarnes). Here is my code.  You are really close.
when you compare color===F, the loop is going to compare #87E2D0 ===F, then #559F4D=== F and so on; therefore, it will never be equal to F.
You need to use charAt(index). Then index in this case will be the index of the letter you want to compare, which is the second letter or index 1.
For example: in the color #87E2D0, index 0 is '#' index 1 is' 8'. 
                       in the color  #FFE0F4 index 0 is '#' index 1 is 'F'.  
I know is late to answer this question, but someone else might come in here looking some information.
```javascript
colors.forEach(color=> (color.charAt(1)=== 'F') && filteredColors.push(color))
```

KRIS NIKOLAISEN · Answer

You are comparing the entire hex color to F. None match therefore none are added. You could compare the second character of color to F by using color[1].

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Dionte Barnes

Dionte Barnes

Using forEach, iterate over the colors array and store the hex colors that start with the letter F (ex. #FF0000) in the

2 Answers

KRIS NIKOLAISEN

KRIS NIKOLAISEN

Henry Blandon

Henry Blandon