Vowels Chanllenge

Hi there! The problem is that for any word that contains a letter not in the vowels list, your loop will run infinitely.

Here's the part of your code that's doing that:

    for letter in word:  #for every letter in the word,
        if letter.lower() not in vowels: #if the letter is not a vowel
            word.append(letter) #append it to the original word

But if we were to send in the word "tree", during the first iteration it will look at that "t". It is not a vowel, so it will be appended onto "tree". At this point, you would have "treet". During the second iteration, it will see "r" and append it as well. Now you have "treetr". This means that for every iteration where the letter is not a vowel, word will be growing in size by another letter that is guaranteed not to be a vowel. Thus, it results in an infinite loop.

As a general rule, it is a good idea to try not to mutate the thing you're looping over during the execution of the loop.

I reworked your code a bit so that it passes and looks similar to yours. Take a look:

def disemvowel(word):
    vowels = ["a", "e", "i", "o", "u"]
    new_word = [] #set up a blank list to hold letters that aren't vowels
    for letter in word:  #for every letter in the word
        if letter.lower() not in vowels:  #if the lower case version is not a vowel
            new_word.append(letter)  #append it to the new list
    new_word = "".join(new_word)  #join our new list so that it is now a string
    return new_word  #return the results of our consonant only list

Hope this helps!