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Start your free trialHussein Amr
2,461 PointsWhat am I doing wrong
help
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(topics):
for v in COURSES:
if topics & (COURSES[v]):
return topics.intersection(COURSES[v])
1 Answer
Ismail KOÇ
1,748 Pointsdef covers(argg):
courses_args = []
for name in set(COURSES.keys()):
if len(argg.intersection(COURSES[name])):
courses_args.append(name)
return courses_args
in your function return in for loop return because all function return once, put it out of loop, define a list in your function and use this function for return your intersection of input argument value of dictionary, look at this code see how much spaces in one line before write any statement.