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JavaScript AJAX Basics (retiring) AJAX Concepts Finish the AJAX Request

What am I doing wrong?

Please help

app.js
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};

request.open('GET', 'footer.html');
function sendAJAX () {
  request.send();
}
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You've incorporated your sending of the request into a function called sendAJAX. but this function was never asked for by the challenge, so it doesn't know to call that function. The only line that should be needed for step two is:

request.send();

Hope this helps! :sparkles: