Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Clayton McDaniels
Clayton McDaniels
5,788 Points
Posted by Clayton McDaniels
Clayton McDaniels
5,788 Points

What am I doing wrong?

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    word = string.lower().split()
    for word in string:
        return {word:word}
print(word_count("I do not like it Sam I Am"))

1 Answer

Josh Keenan
Josh Keenan
20,315 Points
Josh Keenan
Josh Keenan
20,315 Points

Here's my solution:

def word_count(string):
    dictionary = {}
    word = string.lower().split()
    for i in word:
        dictionary[i] = word.count(i)
    return dictionary

I have taken the input and lowercased it all and then split it. Then I have began a for loop to iterate over each word, it then creates a key if there isn't one, and simply counts the instances of the word in the word list.

Hope this helps