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iOS Objective-C Basics (Retired) Functional Programming in C Functions

Posted by Brandon Sherwood
Brandon Sherwood
611 Points

What am I doing wrong here?

was wondering if someone could tell me what I'm doing wrong?

functions.c 
int addTwo (int a, int b) {

  int good = 34;
  int man = 23;
  printf("%d %d\n",good, man);
}
int addTwo () {
return a + b + 8;
}

2 Answers

Joe Ramirez
PLUS
Joe Ramirez
Courses Plus Student 14,366 Points
Joe Ramirez
Joe Ramirez
Courses Plus Student 14,366 Points

Hey Bud,

So, basically the question asks you to have the return type of float from the sum of two float arguments. Since we know that our end result has to be a float then our "addTwo" function would have a "float" instead of an int to which you would also include "float" in the arguments inside the function. 

// returnType addTwo( float args good,  float args man)

float addTwo(float good, float man) {
return good + man;
}

You had it, just a few changes here and there.

Brandon Sherwood
Brandon Sherwood
611 Points

```<p>int addTwo (int a, int b) {

float good = 34; float man = 23; printf("%f %f\n", good, man); } float addTwo(float good, float man) { return good + man; }<p>```

what am i doing wrong?

Joe Ramirez
PLUS
Joe Ramirez
Courses Plus Student 14,366 Points
Joe Ramirez
Joe Ramirez
Courses Plus Student 14,366 Points

Hey,

With the code you posted - you're calling two functions and trying to print one. The "int addTwo(int a, int b)" is not needed because you're not trying to return integer value with integer arguments. It's not asking you to print to the console so you don't have to worry about the printf statement; it's not needed. The last part about implementation is basically asking write the working code without actually filling it out- if that makes sense. So,don't worry about a = 1 or b = 2 etc, etc, just the code. It's more about learning the concept rather than writing a full on function. The code that I posted yesterday or this one will pass you to the next video.

float addTwo(float a, float b) {
return a + b;
}