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Start your free trialJason Thompson
973 PointsWhat am I missing?
This code produces the desired results on my Mac just fine. What am I missing?
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(strarg):
strarg = strarg.lower()
word_list = strarg.split()
dictionary = {}
for base_word in word_list:
word_count = 0
for word in word_list:
if word == base_word:
word_count += 1
dictionary[base_word] = word_count
print(dictionary)
2 Answers
Jennifer Nordell
Treehouse TeacherHi there, Jason! You're not missing much at all. My guess here is that you used print
so that you could see the results of your function, but the challenge asks you to return the dictionary... not print it.
Simply changing your last line to return dictionary
, causes the challenge to pass! Good job!
Jason Thompson
973 PointsI can't believe I missed that. Thanks, Jennifer.