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PHP Object-Oriented PHP Basics (Retired) Properties and Methods Mid-Course Challenge

Harry Gils
Harry Gils
4,322 Points
Posted by Harry Gils
Harry Gils
4,322 Points

What am I missing in this code challenge?

I think I'm creating the getInfo() function correctly but it keeps saying it's wrong. Can someone show / explain what I'm missing here and why?

fish.php 
<?php

class Fish {

  public $common_name;
  public $flavor;
  public $record_weight;

  function __construct($name, $flavor, $record){
    $this->common_name = $name;
    $this->flavor = $flavor;
    $this->record_weight = $record;
     } 

  function getInfo(){
     return "A ". $this->$name . " is an ". $this->$flavor . "flavored fish.  The world record weight is " . $this->$record . ".";

  }

}
$bass = new Fish("Largemouth Bass", "Excellent", "22 pounds 5 ounces");
?>
Steven Joyner
Steven Joyner
5,337 Points

trying the exact same code, the challenge passed for me. It seems your browser just needs a good refresh.

 <?php

class Fish {

  public $common_name;
  public $flavor;
  public $record_weight;

  function __construct($name, $flavor, $record){
    $this->common_name = $name;
    $this->flavor = $flavor;
    $this->record_weight = $record;
     } 

  function getInfo(){
     return "A ".$this->$name . " is an ".$this->$flavor . "flavored fish.  The world record weight is " .$this->$record . ".";

  }

}
$bass = new Fish("Largemouth Bass", "Excellent", "22 pounds 5 ounces");
?>

2 Answers

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

Hi Harry,

You are very close. You are just using the wrong variable names. $this is right, but you don't need the $ for the name, and you need to use the original variable names, not the ones pass in the argument.

function getInfo(){
  return "A ".$this->common_name . " is an ".$this->flavor . "flavored fish.  The world record weight is " .$this->record_weight . ".";
}

Hope that helps. Keep Coding! :)

Harry Gils
Harry Gils
4,322 Points
Harry Gils
Harry Gils
4,322 Points

Thanks guys. I redid it the way you explained it Jason and it worked. Yes, I just noticed that I don't need a $ in front of the name since $this->common_name is the variable.. already a $ there.

thanks. It's making a bit of sense now.