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Start your free trialLogan Valdez
Courses Plus Student 6,741 PointsWhat do I do? (Number Game App challenge)
I am supposed to return the argument of squared and multiply it by itβs length if it cannot be converted into an integer, but I am receiving a SyntaxError for the last line of the program. What should I do to correct this error?
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(a):
try:
if type(a) == int:
return a ** 2
else:
return a * len(a)
1 Answer
ianuweocrs
6,958 PointsHi ! You have to use the try/except blocks (as you started it well), because you have to try if you can convert the parameter as an int, if not, the except block is executed
def squared(a):
try:
return int(a) ** 2
except:
return a * len(a)