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Start your free trialBianca Power
8,094 PointsWhat have I missed?
"Create a function named word_count() that takes a string. Return a dictionary with each word in the string as the key and the number of times it appears as the value."
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(string):
my_dict = {}
string = string.lower()
my_list = string.split()
for word in my_list:
if word in my_list:
my_dict[word] += 1
else:
my_dict[word] = 1
return my_dict
1 Answer
Cody Te Awa
8,820 PointsHi Bianca, You have the right idea and everything looks great is just seems as though you have somewhat a typo at line 17 where your if statement is. You shouldn't be checking if the current word is in the list of words you are looping through but instead checking whether it's in the dictionary you created. That is your only problem, Great work though Bianca! and Happy coding! :) -CodyTheCoder
Bianca Power
8,094 PointsBianca Power
8,094 PointsOf course! Thank you!!