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Python Python Collections (Retired) Dictionaries Word Count

Bianca Power
Bianca Power
8,094 Points

What have I missed?

"Create a function named word_count() that takes a string. Return a dictionary with each word in the string as the key and the number of times it appears as the value."

word_count.py
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.

def word_count(string):

    my_dict = {}

    string = string.lower()

    my_list = string.split()

    for word in my_list:
        if word in my_list:
            my_dict[word] += 1
        else:
            my_dict[word] = 1


    return my_dict

1 Answer

Cody Te Awa
Cody Te Awa
8,820 Points

Hi Bianca, You have the right idea and everything looks great is just seems as though you have somewhat a typo at line 17 where your if statement is. You shouldn't be checking if the current word is in the list of words you are looping through but instead checking whether it's in the dictionary you created. That is your only problem, Great work though Bianca! and Happy coding! :) -CodyTheCoder

Bianca Power
Bianca Power
8,094 Points

Of course! Thank you!!