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Python Python Collections (Retired) Dictionaries Word Count

Posted by Fox guy
Fox guy
1,802 Points

What is counting?

I'm sure I am making this harder than it really is but what is it counting?

word_count.py 
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.

def word_count(sentence):
  string_lower = sentence.lower()
  string_split = string_lower.split()
  word_dict = {}
  count = 0
  for word in string_split:
    word_dict[word] = count
    count += 1 
  return word_dict

2 Answers

AR Ehsan
AR Ehsan
7,912 Points
AR Ehsan
AR Ehsan
7,912 Points 
   def word_count(str):
  strLC = str.lower()
  str_parts = strLC.split()
  word_dict = {}
  #count = 0
  for item in str_parts:
    #if count < len(str_parts):
      if item in word_dict:
        #word = 1
        #count += 1
        #word += 1
        #word_dict.update({str_parts[count - 1] : word})
        word_dict[item] += 1  #<-- look up item and increment the count value
      else:
        #count += 1
        #word = 1
        #word_dict[str_parts[count -1]] = 1
        word_dict[item] = 1 #<-- Create new dictionary key, set value to 1
      continue
    #else:
    #  break
  return (word_dict)
#word_count(str)
Fox guy
Fox guy
1,802 Points

thanks for the breakdown, makes more sense now.

Fox guy
Fox guy
1,802 Points

?