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Start your free trialSahar Nasiri
7,454 PointsWhat is going on?
According to the sample dictionary I get 5 courses from the code below, but I get an error that I need to have 18 courses!!! HOW??? There is only 7 words in that dict!!!
for value in dict_of_teachers.values(): if value not in list_of_courses: list_of_courses.append(value) else: continue return list_of_courses
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(dict_of_teachers):
max_count = 0
max_teacher = ""
for key in dict_of_teachers:
if len(dict_of_teachers[key]) > max_count:
max_count = len(dict_of_teachers[key])
max_teacher = key
else:
continue
return max_teacher
def num_teachers(dict_of_teachers):
return len(dict_of_teachers)
def stats(dict_of_teachers):
list_of_list = []
for key in dict_of_teachers:
list_of_list.append([key, len(dict_of_teachers[key])])
return list_of_list
def courses(dict_of_teachers):
list_of_courses = []
for value in dict_of_teachers.values():
if value not in list_of_courses:
list_of_courses.append(value)
else:
continue
return list_of_courses
2 Answers
Chris Freeman
Treehouse Moderator 68,441 PointsEach value
in the dict_of_teachers
is a list. When you use append
the entire list of a teacher is a appended. 5 teachers, 5 lists.
Instead use extend
list_of_courses.extend(value)
reza sajadian
718 PointsYeah. The same strange problem! Thanks.
Chris Freeman
Treehouse Moderator 68,441 PointsChris Freeman
Treehouse Moderator 68,441 PointsThe example data may differ from the data used by the challenge grader.