What is going on here? I can't figure out the problem

Question

Either it's a bug or I'm an idiot, I'm guessing number 2

trial.py

try():
    def add(n1, n2):
        except(ValueError):
            return(None)
        else():
            return(float(n1)+float(n2))

Answer 1 · 2017-01-05T19:52:06Z

January 5, 2017 7:52pm

try, return and else don't take parentheses
You should put the try block inside of the function. You're not going to try defining this function, the function is definitely getting defined. But inside the function, when it gets called, you're going to try converting what gets passed in into a float. If someone passes in something that can be converted to a float, it won't throw an error. If it can't be converted to a float, it will throw an error, and then it will go into the except block. If except doesn't happen, we go into the else block where you can return the items added together.

Here is my version of it:

def add(n1, n2):
    try: 
        float_sum = float(n1) + float(n2)
    except ValueError:
        return None
    else:
        return float_sum

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