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Ashish Shah
1,468 PointsWhat is the code?
What is the code?
def num_teachers(test2):
return len(test2)
def num_courses(a_dict):
a_list = []
for key in a_dict:
for item in key:
if item not in a_list:
a_list.append(item)
else:
continue
return a_list
3 Answers
james south
Front End Web Development Techdegree Graduate 33,271 Pointsyour indentation is off. the second for loop has to be indented a tab to be inside the first for loop. also the body of the if statement must be a tab in from the if. the else goes at the same level as the if but the rest goes one tab in (right).
Joshua Dam
7,148 PointsYou need to dig into the dictionary a little deeper. All you're pulling out of the dictionary are the lists. You need to get the values inside of the lists. You also don't need to include else: continue. The FOR statement will only run a certain number of times
Also, upon further inspection: using "for item in key:" is pulling out every character from just the keys. So it outputs this: ['A', 'n', 'd', 'r', 'e', 'w', ' ', 'C', 'h', 'a', 'l', 'k', 'y', 'K', 't', 'L', 'o', 'v']
Therefore, you need to use "for key, value" as shown below
for key, value in a_dict.items():
for value in value:
krishnaprasad RS
Courses Plus Student 413 Pointsdef most_courses(teacher_dict):
for name, course in teacher_dict.items():
if max(course):
return name
Ashish Shah
1,468 PointsAshish Shah
1,468 Points"PLEASE PROVIDE SOLUTION FOR THIS"Wow, I just can't stump you! OK, two more to go. I think this one's my favorite, though. Create a function named most_courses that takes our good ol' teacher dictionary. most_courses should return the name of the teacher with the most courses. You might need to hold onto some sort of max count variable.