what is the solution of this question?

Question

how can the round function used for uppercase and lowercase of string?

silly.py

# The first half of the string, rounded with round(), should be lowercased.
# The second half should be uppercased.
# E.g. "Treehouse" should come back as "treeHOUSE"

Answer 1 · 2016-11-07T21:22:10Z

November 7, 2016 9:22pm

I think you misinterpreted the challenge. The challenge is create a function that takes a string return a string with first half in uppercase and second half in lowercase. You are not using the round function to process strings. First thing, you will need to split the string down in half. The reason you are asked to use round is that len(string) could return an even or uneven number. An uneven number would return a float (e.g 5/2=2.5). As you cannot index using a float you use round for the challenge.

round(5/2) # returns 2

So for for a string with 5 characters, the first 2 characters (index 0, 1) are considered your first half and the remaining 3 characters the second half.

def sillycase(myString): 
    length = len(myString)
    split = round(length/2) 
    first_half = myString[:split].lower() # notice the position of the colon
    second_half = myString[split:].upper() # again, notice the position of the colon

    return first_half + second_half

Let me know if you need more help.

Answer 2 · 2016-11-07T21:00:03Z

November 7, 2016 9:00pm

Hey sonam,

I used the round function to find the halfway point (rounded to an integer or whole number) of the string. If the string that is passed into the function's parameter has an even number of characters, you won't need to use the round function, but if the string has an odd number of characters, you will need it so it's good to have it in the function's logic. Here's what I did in case you need a reference.

def sillycase(string):
    halfwayPoint = round(len(string)/2) # get halfway point of function's string argument.
    firstHalf = string[:halfwayPoint].lower() # convert first half of string parameter to lowercase.
    secondHalf = string[halfwayPoint:].upper() # convert second half of string parameter to uppercase.
    return firstHalf + secondHalf

Answer 3 · 2016-11-07T21:15:40Z

November 7, 2016 9:15pm

thanks chris jones.

Answer 4 · 2016-11-07T21:24:21Z

November 7, 2016 9:24pm

thanks for such a good explaination for round function in strings.

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sonam rathore

sonam rathore

what is the solution of this question?

4 Answers

Script Code

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Chris Jones

Chris Jones

sonam rathore

sonam rathore

Chris Jones

Chris Jones

sonam rathore

sonam rathore