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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by MoatazBellah Ghobashy
MoatazBellah Ghobashy
9,518 Points

What is wrong in my code!!

i use this code in a local environment and the code works very good, but here gave error

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(str_word):
    d = dict()
    list_word = str_word.strip().lower().split(" ")
    for word in list_word:
        d.update({word: list_word.count(word)})

    return d

1 Answer

andren
andren
28,558 Points
andren
andren
28,558 Points

The challenge wants to split on all whitespace. While a space is an example of whitespace it not the only example: tabs, line breaks, multiple spaces and other things like that are also classified as whitespace.

Conveniently enough the split method will actually split on all whitespace by default if you don't pass it any arguments, so if you remove your argument to it like this:

def word_count(str_word):
    d = dict()
    list_word = str_word.strip().lower().split()
    for word in list_word:
        d.update({word: list_word.count(word)})

    return d

Then your code will work.

MoatazBellah Ghobashy
MoatazBellah Ghobashy
9,518 Points

Thank you very much :), it's work