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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Refactor Using a Loop

Posted by Anoud Mu
Anoud Mu
3,851 Points

what is wrong with my code?

var i; for ( var i = 2; i => 12; i += 1) { console.log(i) }

i need it to print 12 times from 2 to 24.

2 Answers

Brandon Oakes
seal-mask
.a{fill-rule:evenodd;}techdegree
Brandon Oakes
Python Web Development Techdegree Student 11,501 Points
Brandon Oakes
.a{fill-rule:evenodd;}techdegree
Brandon Oakes
Python Web Development Techdegree Student 11,501 Points

The challenge wants you to print every even number between 2 and 24 into the log. Your code says I =2 and run this loop if i is greater than/equal to 12, which will never happen then.

The code below says: for var i=2 (this 'i' variable currently equals 2)

run this loop while i is <= 24 (less than equal to 24)

i+=2 (and add 2 to every time, so that when I is printed each time in the for loop it will be 2, then 4, then 6, etc until i is greater than 24)

 for ( var i = 2; i <= 24; i += 2) { 
    console.log(i) 
 }

Let me know if this helps

Anoud Mu
Anoud Mu
3,851 Points

Thank you!

Daniel Stewart
Daniel Stewart
3,163 Points
Daniel Stewart
Daniel Stewart
3,163 Points

When you use for loop the var inside the loop is local to that loop.

Breakdown 4 steps

1 var i = 2. Starts the varivale with value of 2

2 i < 24 condition true as 2 is less than 24 (when false the loop will stop step 3)

3 ++2 or +=2 this will increment by 2 the var i that you declared in the loop. . 4{} code block will run each time the loop condition is true.

Anoud Mu
Anoud Mu
3,851 Points

Thank you!