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JavaScript AJAX Basics (retiring) Programming AJAX Create a callback

Posted by Israt Ali
Israt Ali
5,358 Points

What is wrong with my code?

How an anonymous function is not created here

app.js 
var xhr = new XMLHttpRequest();
xhr.onreadystatechane = function(){

xhr.open('GET', 'sidebar.html');
   xhr.send();
};
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>

1 Answer

Marcus Parsons
Marcus Parsons
15,719 Points

Hi Israt,

It looks like you're missing a letter "g" from inside the word "change" in your onreadystatechange event. Also, the function doesn't extend to the open() and send() functions, so your curly brace should end before those functions are called:

var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function () {}
xhr.open('GET', 'sidebar.html');
xhr.send();