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PHP Build a Simple PHP Application Wrapping Up The Project Objects

Posted by Matt Ferguson
Matt Ferguson
19,404 Points

What is wrong with my conditional statement?

<?php include("class.palprimechecker.php"); $checker = new palprimechecker(); $checker->number = 17;

echo "The number". "$checker->number(17)" . " "; if($checker->isPalprime()) { echo "is"; } else { echo "is not"; } echo " a palprime.";

?>

1 Answer

Paul Mather
Paul Mather
3,313 Points
Paul Mather
Paul Mather
3,313 Points

You don't need to pass a value to ->number since it's defined in $checker. You don't need the " before the $checker->number(17) since what goes after your concatenating is a variable and not a string. You should also delete the . " " directly after the number()