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Python Python Basics (2015) Letter Game App Even or Odd Loop

selcuk baran
selcuk baran
3,526 Points
Posted by selcuk baran
selcuk baran
3,526 Points

What is wrong with the code?

import random start=5 def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2

while start>=0:
    a=random.randint(1,99)
    if even_odd(a)=True:
        print ('{} is even').format(a)
    else:
        print('{} is odd').format(a)

start=start-1

even.py 
import random
start=5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

    while start>=0:
        a=random.randint(1,99)
        if even_odd(a)=True:
            print ('{} is even').format(a)
        else:
            print('{} is odd').format(a)
start=start-1

3 Answers

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points 
if even_odd(a) = True:

On the line above Python caused an error because Python thought you wanted to assign the variable even_odd(a) to True, since you used one equal sign. To fix this use two equal signs like this:

if even_odd(a) == True:

Good luck! ~alex

selcuk baran
selcuk baran
3,526 Points
selcuk baran
selcuk baran
3,526 Points

Thanks. I tried it but not a solution yet

ronakeogh
ronakeogh
30 Points

Can you post the challenge task please?

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

Try doing the .format() stuff inside the print function also :)

Change this:

print ('{} is even').format(a)

Into this:

print ('{} is even'.format(a))

And do this for the other prints also.

Good luck! ~alex

NOTE: You must do this and the other answer above :)