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Python Python Collections (Retired) Dictionaries Word Count

What words are supposed to be used for this exercise?

I did my coding and is doing exactly what is expected and I know this because I've tested out of the workroom locally in my own python install and it works! but when I do the exercise the result says:

"Bummer! Some of the words seem to be missing!"

Previously in another exercise where we were supposed to get "kaoa" (letters from oKlAhOmA) code was right but I was just not testing it with the right word so I guess I might be using the wrong string on this exercise too.

Can someone please tell what string should I test the word_count.py code with?

Thank you.

word_count.py
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(dale):
    dale = "I am that I am"
    eldir = {}
    vez = 0
    palabras = dale.split(' ')
    print("Palabras = ", len(palabras))
    for palabra in palabras:
        if palabra in eldir.keys() :
            eldir[palabra] = eldir[palabra] + 1
        else:
            eldir[palabra] = 1
    return(eldir)

cuero = {}
word_count(cuero)

2 Answers

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,426 Points

You are hard-coding the value of your function argument date with the string "I am that I am". Remove or comment out that line so the function can be used with other input data.

Two issues in your test code, First,word_count argument is a string not a dict. Second, since cuero is empty, There is nothing for the function to process:

cuero = {}
word_count(cuero)

Change this lines to:

cuero = "This test is a test string that is"
word_count(cuero)
dale = "I am that I am"
word_count(dale)

@chrisfreeman3 @chris freeman

Thank you so much, that make sense and worked perfectly.

@chrisfreeman3 @chris freeman

Thank you so much, that make sense and worked perfectly.