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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Andriy Bobrovych
Andriy Bobrovych
4,781 Points
Posted by Andriy Bobrovych
Andriy Bobrovych
4,781 Points

what wrong?

what wrong in this code?

string_factory.py 
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(items):
    result = []
    for i in items:
        result.append(template.format(**i))
    print(result)

1 Answer

Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points

It's to be returned through the function and not printed my friend, you already solved it.

copy pasted the below content from my previous answer...

Yeah, its kinda tricky to understand but may be this would help you.

# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(listt):
    retString = [];
    for key in listt:
        retString.append( template.format(name=key["name"], food=key['food']));
    return retString;

So get it done using '**' operator, we could use following code and then we don't have to specify what is "name" and "food" for the template.

def string_factory(listt): 
    ret_string = [] 
    for key in listt: 
        ret_string.append(template.format(**key) );
    return ret_string 
string_factory(listt);

I dont know it would work, as i never tried before. But try searching the questions related to the topic, it would help you find your answers faster and you don't have to wait in case if someone has already asked it. I know this because i answered this few hours back. :). Have fun.

Hope this helps!