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Python Python Collections (2016, retired 2019) Dictionaries Word Count

dog gone
dog gone
5,646 Points
Posted by dog gone
dog gone
5,646 Points

What wrong with my code? Tt runs fine in workshop but can't pass the test.

def word_count(string): dicti={} string_lower=string.lower() string_list=string_lower.split(' ')
for word in string_list: dicti[word]=string_list.count(word) return dicti

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    dicti={}
    string_lower=string.lower()
    string_list=string_lower.split(' ')    
    for word in string_list:
        dicti[word]=string_list.count(word)
    return dicti

1 Answer

Ines Fazlić
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.a{fill-rule:evenodd;}techdegree
Ines Fazlić
Python Web Development Techdegree Student 9,569 Points
Ines Fazlić
.a{fill-rule:evenodd;}techdegree
Ines Fazlić
Python Web Development Techdegree Student 9,569 Points

Hi, when you make a list with .split() try just making .split() and not .split(' ') and it should work. Then it will take a space as a separator and make every word an item in the list.