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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Vedang Patel
Vedang Patel
7,114 Points
Posted by Vedang Patel
Vedang Patel
7,114 Points

What's wrong I've done it perfectly

please find the mistake!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(text):
    rand = {}
    words = text.split(" ")
    number = 1
    for word in words:
        rand[word] = number
        number += 1
    return rand

1 Answer

Seth Killian
Seth Killian
2,525 Points

Hi Vedang, you're close!

In your for loop, try putting an if statement to check to see if the letter exists in the dictionary already.

def word_count(string):
    d = {}
    for letter in string.lower().split():
        if letter in d:
            d[letter] += 1
        else: d[letter] = 1
    return d
Vittorio Somaschini
Vittorio Somaschini
33,371 Points
Vittorio Somaschini
Vittorio Somaschini
33,371 Points

Hi Seth.

I have changed your comment into an answer ;)

Vitto