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Start your free trialMangesh Somvanshi
3,521 Pointswhats wrong with my code it work well in my local.
def word_count(x): x = x.lower() items = x.split() countr = dict()
for i in items:
if not i in countr:
countr[i] = 1
else:
countr[i] += 1
print countr
word_count("I am that I am")
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(x):
x = x.lower()
items = x.split()
countr = dict()
for i in items:
if not i in countr:
countr[i] = 1
else:
countr[i] += 1
print countr
word_count("I am that I am")
1 Answer
Matthew Rigdon
8,223 PointsI believe your code works fine. Just make sure to change your last line to return instead of print since we are working with a function.
Mangesh Somvanshi
3,521 PointsMangesh Somvanshi
3,521 PointsThanks matthew!!!! it worked!