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Start your free trialPincemail Sebastien
Courses Plus Student 2,411 Pointswhats wrong with my function
Hello guys ,
i can't get out of this task , could you help to understand how can i count and update properly this dict. Thank you for help
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(sentence):
word_dict = dict()
count_dict = dict()
count = 0
sentence_list = sentence.split()
for word in sentence_list:
word_dict[word] = count
if word in word_dict:
word_dict[word] = count + 1
count_dict.update(word_dict)
return word_dict
1 Answer
alex novickis
34,894 PointsI don't want to give you the answer in a cut and pastable form directly but I will instead ask a couple questions
(1) count_dict - you don't test this anywhere and you don't return it
(2) you are missing something from line 3 of the comments
(3) for each word you find in the sentence you always set the count of that word to 0 So if you have a sentence like "a a a a a a" you set the count 6 times to zero, should only be one time check what you are meaning to do exactly in this line word_dict[word] = count