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Dê Gìa
iOS Development Techdegree Student 26,430 Pointswhat's wrong with my solution ???
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
Your code goes below here
messy_list.insert(3,messy_list.pop(0)) messy_list.insert(3,messy_list.pop(0)) messy_list.insert(3,messy_list.pop(0))
"please use insert and pop in my solution ?? "
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
messy_list.insert(3,messy_list.pop(0))
messy_list.insert(3,messy_list.pop(0))
messy_list.insert(3,messy_list.pop(0))
2 Answers
Sneha Nagpaul
10,124 PointsFrom 3 to 0. Your solution moves the contents from 0 to 3.
Meg Goodwin
8,297 PointsFor .insert() you want to first include the index where you want the value to go (in this case "0") and then the value you want to insert (in this case "messy_list.pop(3)". Hope this helps.