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Python Python Basics (2015) Shopping List App Continue

What's wrong with the code ?

Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

breaks.py
def loopy(items):
    for item in items:
        if item.index[0] == "a":
            continue
        else:
            print(item)

2 Answers

Julian Gutierrez
Julian Gutierrez
19,201 Points

Very close, you don't need ".index" on your if conditional.

 if item[0] == "a":

Atul, looking at your code:

def loopy(items):
    for item in items:
        # item is a list, to find first index of a list, do item[0]
        if item.index[0] == "a":
            continue
        else:
            print(item)

If you have any other questions I will update my answer, if you do not have any other questions:

Remember to upvote and to choose the best answer so that your question receives a checkmark in forums.

Kind regards,

Leo