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Python Python Collections (Retired) Dictionaries Word Count

Sean Flanagan
Sean Flanagan
33,235 Points
Posted by Sean Flanagan
Sean Flanagan
33,235 Points

What's wrong with this?

Hi.

Can someone tell me where I've gone wrong here please?

TIA

Sean

word_count.py 
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(string):
    my_dict = {}
    for word in my_list:
        if word in my_dict:
            count = 1
    return count

1 Answer

Amir Eskandari
Amir Eskandari
9,153 Points
Amir Eskandari
Amir Eskandari
9,153 Points

Hey Sean,

I would take a look at the discussion here: https://teamtreehouse.com/community/create-a-function-named-wordcount-that-takes-a-string-return-a-dictionary-with-each-word-in-the-string-as-the-key

There's quite a bit more to this problem, but reading that discussion should help you solve it.