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thanh trung
4,246 Pointswhat's wrong with this?
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(string):
string.lower()
string.split()
dic = {}
for word in string:
if word in dic:
dic[word] +=1
else:
dic[word] = 1
return string
1 Answer
Kenneth Love
Treehouse Guest TeacherStrings are immutable, so calling methods on them return new strings instead of changing the string in place. So start with string = string.lower() and string = string.split().
You'll also want to return dic instead of string, since your function needs to return the counts.