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Start your free trialMUZ140515 Herbert Chirwa
2,589 Pointswhats wrong with this code
stuck don't know were l,m getting it wrong
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
def members(my_dict, my_list):
for item in my_list:
if item in my_dict:
my_dict[item] += 1
else:
my_dict[item] = 1
return my_dict
1 Answer
Erick Kusnadi
21,615 PointsThe code should be retuning a single number, but it returns the entire dictionary. It looks like the code is adding to the dictionary, but the code should instead count the number of items in the list, that is also in the dictionary.
def members(my_dict, my_list):
count = 0
for item in my_list:
if item in my_dict:
count += 1
return count
MUZ140515 Herbert Chirwa
2,589 PointsMUZ140515 Herbert Chirwa
2,589 Pointsthanx man realised my mistake