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Python Python Collections (2016, retired 2019) Tuples Packing

kyle gonzalez
kyle gonzalez
3,965 Points

When I compile my answer it doesn't run; when I run it in my text editors it compiles. Any insight into other solutions?

def multiply(*args): f = lambda a,b: a*b product = reduce(f, *args) return product

twoples.py
def multiply(*args):
    f = lambda a,b: a*b
    product = reduce(f,*args)
    return product
kyle gonzalez
kyle gonzalez
3,965 Points

Problem: Let's play with the *args pattern. Create a function named multiply that takes any number of arguments. Return the product (multiplied value) of all of the supplied arguments. The type of argument shouldn't matter. Slices might come in handy for this one.

1 Answer

Steven Parker
Steven Parker
231,275 Points

I can see two issues:

  • you need "from functools import reduce"
  • there should be no "splat" (scatter operator) in the call to reduce

I'm surprised you didn't get any errors!

kyle gonzalez
kyle gonzalez
3,965 Points

Ah so I was missing the reduce function from the functools library?

When I compile the code in: Python 3.6.1 (default, Dec 2015, 13:05:11) [GCC 4.8.2] on linux

With * operator, it returns the desired value (24) from a list of [1,2,3,4]. Without the * operator, it returns [1,2,3,4]. In the Treehouse editor, you are correct: The code is accepted without the * operator. Could you provide some more insight as to why it is not needed? Thank you!

Steven Parker
Steven Parker
231,275 Points

The scatter operator converts the list into individual arguments, but the "reduce" function expects a list as the 2nd argument.

On the other hand, the "multiply" function itself is intended to take "any number of arguments" and multiply them. So you would not pass it a list. A test call might look like this: "multiply(1, 2, 3, 4)".

Be careful about testing a challenge in an external REPL.
If you have misunderstood the challenge, it's also very likely that you will misinterpret the results.