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Python Python Collections (Retired) Dictionaries Teacher Stats

Posted by Spencer Johnson
Spencer Johnson
19,708 Points

When I test this code in workspaces it is formating list as instructed [<name>, <number of classes>] , so what is wrong?

schedule = {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'], 'Kenneth Love': ['Python Basics', 'Python Collections'], 'Spencer Johnson': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations', 'Python Basics', 'Python Collections']}

def stats(schedule):
  list = []
  for (key, value) in schedule.items():
    list.append((key, len(value)))
  return list
print(stats(schedule))
teachers.py 
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
schedule = {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'], 'Kenneth Love': ['Python Basics', 'Python Collections'], 'Spencer Johnson': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations', 'Python Basics', 'Python Collections']}


def most_classes(schedule):
  most_classes = ""
  max_count = 0

  for teacher in schedule:
    if len(schedule[teacher]) > max_count:
           max_count = len(schedule[teacher])
           most_classes = teacher
  return most_classes

print(most_classes(schedule))

def num_teachers(schedule):
  count = 0
  for teacher in schedule:
    count = count + 1
  return count
print(num_teachers(schedule))

def stats(schedule):
  list = []
  for (key, value) in schedule.items():
    list.append((key, len(value)))
  return list
print(stats(schedule))

1 Answer

Spencer Johnson
Spencer Johnson
19,708 Points

I change one pair or () to [] instead and viola!! It passes.

I did not see anyone else use the approach of using the items() method call

for (key, value) in schedule.items():

but it appears to be working like a charm.

def stats(schedule):
  list = []
  for (key, value) in schedule.items():
    list.append([key, len(value)])
  return list
print(stats(schedule))