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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by alekseibingham
alekseibingham
4,491 Points

When running this code in another IDE I am getting the correct results. Although here It is declared as incorrect.

Its telling me to make sure I lowercase the string, although that is the very first thing I do aside from splitting the string up into a list to iterate through each word.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
  list_of_words = string.lower().split()

  dict = {}

  counter = 1

  for word in list_of_words:
    for key in dict.keys():
      if (word == key):
        counter += 1
    dict[word] = counter
    counter = 1


  return dict

1 Answer

Kirsten Smith
Kirsten Smith
3,484 Points
Kirsten Smith
Kirsten Smith
3,484 Points

You are only indenting your function with 2 spaces. Remember to indent with 4 and it should work.