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Start your free trialChris Galatis
3,089 PointsWhen we give a method an argument, what is the argument actually doing?
I am a bit confused as to what the argument is used for when we define a method
class TodoList
attr_reader :name, :todo_items
def initialize(name)
@name = name
@todo_items = []
end
def add_item(name)
todo_items.push(TodoItem.new(name))
end
def contains?(name)
end
def find_index(name)
index = 0
found = false
todo_items.each do |item|
found = true if item.name == name
break if found
index += 1
end
if found
return index
else
return nil
end
end
end
2 Answers
Dylan Shine
17,565 PointsWhen we provide an argument to a method in Ruby, we are creating a local variable for our method to use/operate on the method object we provided.
def initialize(name)
@name = name
@todo_items = []
end
For the standard initialize method, we provide an argument called name, probably in the form of a String, that we will use to assign the instance variable @name. We are simply passing a variable or value to that method, and the method will do something with or to it.
my_num = 1
def do_something_to_num(number)
number *= 2
end
do_something_to_num(my_num) #=> 2
Here we create a variable my_num, and define a method do_something_to_num that takes one argument, number. Second we invoke the our newly defined method, passing in the variable my_num for it's argument.
To answer your question, arguments are representing/providing values for our methods, so your methods can perform whatever their trying to do.
Best,
Dylan
Chris Galatis
3,089 Pointsso if i am understanding it right the arguments we give the methods are kind of like characteristics of the method? like the argument is what the method does? as in this code
my_num = 1 def do_something_to_num(number) number *= 2 end
do_something_to_num(my_num) #=> 2
so the do_something_to_num method is taking an argument (number) and that arguments multiples by 2. so when the do_something_to_num method is called in the second part, it takes the my_num variable that we set equal to 1 and *= 2 onto my_num if i am understanding correctly?
Dylan Shine
17,565 PointsCorrect