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dima Dima
901 Pointswhere is the mistake here
I need to loop through the list and print the item's index 0 if it Is not an A
def loopy(items):
for item[index]:
index=0
if items[index]=a:
continue
else:
print (items[index])
index=index+1
print (itemes(index))
2 Answers
Cindy Lea
Courses Plus Student 6,497 PointsYou have a few things different & the code could be simplified to this:
def loopy(items):
for item in items:
if item[0] == "a":
continue
print(item)
'''
Russell Sawyer
Front End Web Development Techdegree Student 15,705 PointsYou have the right idea but you need to make a few changes. The for loop allows you to iterate through a list of items using a "throw away" variable, in this case 'item'.
def loopy(items):
for item in items: # iterate through items
if item[0] == 'a': # == compares the two items to see if they are the same. = assigns value to variables, but any string needs to be in quotes or it will produce an error
continue
print(item)