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Python Python Basics (2015) Letter Game App Even or Odd Loop

while loop and random.randint

Hello, this is the task :(Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1.) I tried this codes to solve it but it did not work, can you help me figure out what is wrong with it !! sincerely,,

even.py
import random
start = 5
while True:
    num = random.randint(1,99)    
    def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
    print("{}is even".format(num))

else:
    print("{} is odd".format(num))

start = start -1

1 Answer

Steven Parker
Steven Parker
230,995 Points

Here's a couple of hints:

  • do not modify the provided even_odd function, add your code after it
  • you can use that function for testing your random numbers